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Might Waxwings breed? (1 Viewer)

As you say, there are three options, however they are not all as likely - it is twice as likely that there will be a male and a female than 2 males or two females.

I can't get past the fact that there can either be 2 males, 2 females or one of each.
But then, I did pass on the coffe.

Phil
 
:-O

It should be the same as with coins, which I've since remembered -

Flip 2 coins (or the same coin once, then again);

chance of 2 heads - 25%
chance of 2 tails - 25%
chance of head, then tail - 25%
chance of tail, then head - 25%

All eventualities covered, an odd pairing (any combination of a head and a tail) being 25+25 =50%

(Which is basically what James Emerson said in post #14)

Flipping Waxwings, would be more fun though!


Indeed, Dan! Sorry, too much red wine today... ;)

And to think my daughter got a maths PhD. It's definitely not in the genes...

Just as long as you don't get red wine on your best jeans ...
 
As you say, there are three options, however they are not all as likely - it is twice as likely that there will be a male and a female than 2 males or two females.

Isn't that dependent on knowing the ratio of males to females in the population?

This hangover is starting early.

Phil
 
Just as long as you don't get red wine on your best jeans ...
I think I should get some of those French breathalyzer thingies, and always use one before posting on BirdForum.

PS. I'd probably still post, but I could include a qualifying footnote stating whether I was pissed or not. B :)
 
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I'm with Phil

option one / two males
option two / two females
option three / a pair

so a one in three chance they are a couple so 33%

but I do get the increased odds of is the male that bird or the other adding to the odds
be great to think they had hung around to breed though whatever the odds.

B :)
 
I'm with Phil

option one / two males
option two / two females
option three / a pair

so a one in three chance they are a couple so 33%
No! Dan and James are right...
  1. ♂♂
  2. ♂♀
  3. ♀♂
  4. ♀♀
So 2/4 (50%) are winning combinations, assuming romance is in the air...
 
No! Dan and James are right...
  1. ♂♂
  2. ♂♀
  3. ♀♂
  4. ♀♀
So 2/4 (50%) are winning combinations, assuming romance is in the air...

;) surely that only applies if you are bothered about which one is the male and which one is the female? if you are only interested in them being a pair then it has to be 1/3

but then again perhaps you're right and I'm drunk? B :)
 
I'm with Phil

option one / two males
option two / two females
option three / a pair

so a one in three chance they are a couple so 33%

but I do get the increased odds of is the male that bird or the other adding to the odds
be great to think they had hung around to breed though whatever the odds.

B :)

Dan is right a few posts up - it's definitely a 50% chance of being a pair. There are 4 options:

2 males
2 females
A male and a female
A female and a male

All of which have the same probability. Two of the options make a pair though, so the chance of 2 birds being a pair are 50/50, barring getting complicated with sex ratios and pre breeding behaviour.
 
What about if there are three? And how many before you could be 100% there was a pair?.......this could go on.....B :)
 
50% chance they are a M/F but what odds that only one of them is a minger? That would reduce breeding potential.
 
3:)
I still only see a third in it as I wouldn't care which is male and which is female therefore only three situations

both male
both female
a pair

so a one in three chance of them being a pair.....33% if you like

the 50% only kicks in if you start to think male and female bird or female and male bird but all we need to know is are they a pair.

still I'm not losing any sleep over it and I do seem to be the only person here who's going with the 33% option so perhaps I'm wrong but regardless it would still be good to think there was a pair and they could find some way of breeding in the UK but don't take any gambling advise from me as I'm clearly not good at working out the odds. :smoke:
 
Take one Waxwing. That bird has to be a male or a female. In this example, say it is a male.

Take another Waxwing. It is 50% chance it is a female, therefore 50 % chance of a pair.

And just for those on the wine (still), let's assume the first bird is a female. Now we come to the second bird; there is a 50% chance of this being a male and so the theory holds true again.
 
I still only see a third in it as I wouldn't care which is male and which is female therefore only three situations

both male
both female
a pair

so a one in three chance of them being a pair.....33% if you like

... so perhaps I'm wrong

You are.


still I'm not losing any sleep over it

You should.

Go and get 2 coins. Decide that heads are male and tails are female (or perhaps the other way around if you're a feminist). Flip them both, and write down the outcome (heads or tails OR male and female if you like).

Do this a hundred times.

Report back on here how many times you had -

a) 2 heads
b) 2 tails
c) a head and a tail


Don't have too much fun.

:t:


(Edit: Waxwings don't like being flipped (they tend to fly away or worse), so you have to use something else, like coins, even if they are unlikely to actually produce offspring etc).
 
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Although with coins you know that there are exactly the same number of heads as tails. Unless we know that there exactly the same number of males as females in the waxwing population as a whole then surely that analogy doesn't stand up.

Phil
 
Take one Waxwing. That bird has to be a male or a female. In this example, say it is a male.

Take another Waxwing. It is 50% chance it is a female, therefore 50 % chance of a pair.

And just for those on the wine (still), let's assume the first bird is a female. Now we come to the second bird; there is a 50% chance of this being a male and so the theory holds true again.

Now that makes sense! I think you've won me over ;)
 
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